Question

The sum of three consecutive numbers odd numbers is one hundred and eleven
What is the smallest of the three numbers

Answer 1

1113 = 37. So,
35+37+39 = 111
35 is the smallest

Answer 2

Let's assume that the smallest of the three consecutive odd numbers is x.

Then, the next two odd numbers would be x+2 and x+4.

According to the problem, the sum of these three numbers is 111:

x + (x+2) + (x+4) = 111

Simplifying the equation:

3x + 6 = 111

Subtracting 6 from both sides:

3x = 105

Dividing both sides by 3:

x = 35

Therefore, the smallest of the three consecutive odd numbers is 35.