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wo pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The...Asked by J.J Powell
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid?
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Let's assume that after t minutes, the two vats will have the same amount of liquid.
Let V be the amount of liquid in the first vat after t minutes, and let W be the amount of liquid in the second vat after t minutes.
The amount of liquid in the first vat after t minutes is given by:
V = 6t
The amount of liquid in the second vat after t minutes is given by:
W = 28 + 4t
To find when the two vats have the same amount of liquid, we need to solve the equation:
V = W
6t = 28 + 4t
2t = 28
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.
Let V be the amount of liquid in the first vat after t minutes, and let W be the amount of liquid in the second vat after t minutes.
The amount of liquid in the first vat after t minutes is given by:
V = 6t
The amount of liquid in the second vat after t minutes is given by:
W = 28 + 4t
To find when the two vats have the same amount of liquid, we need to solve the equation:
V = W
6t = 28 + 4t
2t = 28
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.
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