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Two pumps are filling a pool. One of them is high power and can fill the pool alone in 2 hours less time than the other can do so. Given that, working together, both pumps can fill the pool in 144 minutes, how long, in hours, will it take the powerful pump to fill the pool alone?
Answers
Answered by
oobleck
1/x + 1/(x-2) = 60/144
now just solve for x
now just solve for x
Answered by
R_scott
s = smaller pump fill time ; b = bigger pump fill time
s = b + 120
(144 / s) + (144 / b) = 1
[144 / (b + 120)] + (144 / b) = 1
144 b + 144 b + (144 * 120) = b (b + 120)
0 = b^2 - 168 b - 17280
convert answer to hours
s = b + 120
(144 / s) + (144 / b) = 1
[144 / (b + 120)] + (144 / b) = 1
144 b + 144 b + (144 * 120) = b (b + 120)
0 = b^2 - 168 b - 17280
convert answer to hours
Answered by
REEEEEEEe
The answer is 4 hours
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