Let's assume that after t minutes, the two vats will have an equal amount of liquid.
The amount of liquid in the first vat after t minutes will be 6t (since it is filling at a rate of 6 gallons per minute).
The amount of liquid in the second vat after t minutes will be 10 + 4t (since it already has 10 gallons and is filling at a rate of 4 gallons per minute).
To find when the two vats will have an equal amount of liquid, we can set these two expressions equal to each other:
6t = 10 + 4t
Simplifying this equation, we get:
2t = 10
t = 5
Therefore, the two vats will have an equal amount of liquid after 5 minutes.
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid.
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1 answer