Question
Calculate the mass of silver trioxonitrate in500cm3 of0.01m AgNo3 in gramme.
Answers
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To calculate the mass of silver trioxonitrate (AgNO3) in 500 cm3 of 0.01 M AgNO3, we need to use the formula:
mass = concentration x volume x molar mass
where:
- concentration = 0.01 M (given)
- volume = 500 cm3 = 0.5 L (given)
- molar mass of AgNO3 = 107.87 g/mol (from periodic table)
Substituting the values, we get:
mass = 0.01 x 0.5 x 107.87
mass = 5.3935 g
Therefore, the mass of silver trioxonitrate in 500 cm3 of 0.01 M AgNO3 is 5.3935 grams.
mass = concentration x volume x molar mass
where:
- concentration = 0.01 M (given)
- volume = 500 cm3 = 0.5 L (given)
- molar mass of AgNO3 = 107.87 g/mol (from periodic table)
Substituting the values, we get:
mass = 0.01 x 0.5 x 107.87
mass = 5.3935 g
Therefore, the mass of silver trioxonitrate in 500 cm3 of 0.01 M AgNO3 is 5.3935 grams.