Asked by Fortune
Calculate the mass of a silver deposited when a current of 1.5A passed through a solution of a silver salt for 70 minutes (Ag=108,line Friday=96500c
Answers
Answered by
DrBob222
How many coulombs? That's
C = amperes x seconds
C = 1.5 A x 70 min x (60 sec/min) = 6300
96,500 C will deposit 108 g Ag so 6300 C will deposit
108 x (6,300/96,500) = ?
C = amperes x seconds
C = 1.5 A x 70 min x (60 sec/min) = 6300
96,500 C will deposit 108 g Ag so 6300 C will deposit
108 x (6,300/96,500) = ?
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