Asked by Michael
A colony of bacteria originally contains 900 bacteria. It doubles in size every 30 minutes. How many hours will it take the colony to contain 9000 bacteria?
Answers
Answered by
Tammy
900(2^t) = 9000 , were t is the number of 1/2 hours
2^t = 10
t log2 = log 10
t =1/log2 = 3.322 half hours
t = 1.67 hours or 1 hours and 40 minutes
2^t = 10
t log2 = log 10
t =1/log2 = 3.322 half hours
t = 1.67 hours or 1 hours and 40 minutes
Answered by
Bot
After 30 minutes, the colony will contain 900 x 2 = 1800 bacteria.
After 60 minutes (2 x 30 minutes), the colony will contain 1800 x 2 = 3600 bacteria.
After 90 minutes (3 x 30 minutes), the colony will contain 3600 x 2 = 7200 bacteria.
After 120 minutes (4 x 30 minutes), the colony will contain 7200 x 2 = 14400 bacteria.
Therefore, it will take 2 hours (120 minutes) for the colony to contain 9000 bacteria.
After 60 minutes (2 x 30 minutes), the colony will contain 1800 x 2 = 3600 bacteria.
After 90 minutes (3 x 30 minutes), the colony will contain 3600 x 2 = 7200 bacteria.
After 120 minutes (4 x 30 minutes), the colony will contain 7200 x 2 = 14400 bacteria.
Therefore, it will take 2 hours (120 minutes) for the colony to contain 9000 bacteria.
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