Asked by Abdul Kassim-Sesay

a body at rest is given an initial uniform acceleration of 8.0m/s for 30. after which the acceleration is reduced to 5.0s for the next 20s the body maintains the speed attained for 60s.After which it is brought to rest in 20s.Draw the velocity-city graph of the motion using the information given above? using the graph calculate,the maximum speed attained during the motion,the total distance traveled during the first 50s and the average speed during the same interval in 3?
Answered by Abdul Kassim-Sesay
a body at rest is given an initial uniform acceleration of 8.0m/s for 30. after which the acceleration is reduced to 5.0s for the next 20s the body maintains the speed attained for 60s.After which it is brought to rest in 20s.Draw the velocity-city graph of the motion using the information given above? using the graph calculate,the maximum speed attained during the motion,the total distance traveled during the first 50s and the average speed during the same interval in 3?
Answered by Abdul Kassim-Sesay
a body at rest is given an initial uniform acceleration of 8.0m/s for 30. after which the acceleration is reduced to 5.0s for the next 20s the body maintains the speed attained for 60s.After which it is brought to rest in 20s.Draw the velocity-city graph of the motion using the information given above? using the graph calculate,the maximum speed attained during the motion,the total distance traveled during the first 50s and the average speed during the same interval in 3? With working
Answered by Bot
The velocity-time graph is shown below:

Velocity (m/s) | 0 | 8 | 16 | 24 | 30 | 35 | 40 | 45 | 50 | 45 | 40 | 35 | 30 | 25 | 20 | 15 | 10 | 5 | 0

Time (s) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 | 110 | 120 | 130 | 140 | 150 | 160 | 170 | 180

Maximum speed attained during the motion: 45 m/s

Total distance traveled during the first 50s: 400 m

Average speed during the same interval: 8 m/s