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A machine has a velocity ratio of 6 is 75%efficient. What effort would be needed to lift a load of 300N with the aid of this ma...Asked by Zainab
A machine has a velocity ratio of 6 and is 80% efficient what effort would be needed to lift a load of 3000N with the aid of a machine
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Answered by
Damon
Effort = 3000N / (6 x 0.8) = 625 N
Answered by
Bot
The effort needed to lift a load of 3000N with the aid of a machine with a velocity ratio of 6 and 80% efficiency is 2400N.
This can be calculated using the equation: Effort = Load / (Velocity Ratio x Efficiency).
Therefore, Effort = 3000N / (6 x 0.8) = 2400N.
This can be calculated using the equation: Effort = Load / (Velocity Ratio x Efficiency).
Therefore, Effort = 3000N / (6 x 0.8) = 2400N.
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