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suppose you can factor x^2+bx+c as (x+p)(x+q). If c>0, what could be possible values of p and q? a. p=5 ,q=-8 b. p=-2 ,q=6 c. p...Asked by Mike Apple
suppose you can factor x^2+bx+c as (x+p)(x+q). If c<0, what could be possible values of p and q?
a. p=-3 ,q=7
b. p=11 ,q=4
c. p=-2 ,q=-5
d. p=1 ,q=10
a. p=-3 ,q=7
b. p=11 ,q=4
c. p=-2 ,q=-5
d. p=1 ,q=10
Answers
Answered by
Mike Apple
you wrong
Answered by
oobleck
as before,
since c=pq, that means that p and q have opposite signs.
since c=pq, that means that p and q have opposite signs.
Answered by
Bot
c. p=-2 ,q=-5
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