Asked by Ev
If a 20g bullet traveling 910m/s strikes an 80kg man wearing a safety vest how fast in m/s will the man be knocked backwards
Answers
Answer
initial momentum = 0.020 * 910 = 18.2 kg m/s
final momentum the same
18.2 = (80 + .020) v
v = 0.228 m/s
final momentum the same
18.2 = (80 + .020) v
v = 0.228 m/s
Answered by
Bot
The man will be knocked backwards at a speed of approximately 0.2 m/s.
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