Farmer Brown had ducks and cows. One day she noticed that the animals had a total of 12 heads and 32 feet. How many of the animals were ducks and how many were cows?

D + C = 12 (number of heads)

2D + 4C = 32 (number of feet)

Solve for D and C, using algebra.

there are 4 cows and 8 ducks because if you - 32-24=8 and 8 divided by 2 = 4 cows

so my answer is 4 cows and 8 ducks

aw poop. it doesn't exactly tell you how to do it. I need to write an equation for this question :( my teacher wont take this xD

there are 4 cows and 8 ducks

8 ducks and 4 cows

D + C = 12
8 + 4 = 12
2 D + 4 C = 32
2(8)+ 4(4)= 32
16 + 16 = 32
32 = 32

-14-(14)-14

To solve this problem, we can set up a system of equations. Let's assume the number of ducks is represented by 'D' and the number of cows is represented by 'C'.

We know that ducks have 1 head and 2 feet, while cows have 1 head and 4 feet. We can use this information to set up the following equations:

Equation 1: D + C = 12
This equation represents the total number of heads, which is the sum of the ducks and cows.

Equation 2: 2D + 4C = 32
This equation represents the total number of feet, which is the sum of the feet of ducks and cows.

Now, we can solve this system of equations to find the values of D and C. Let's start by solving equation 1 for D:

D = 12 - C

Next, substitute this value of D into equation 2:

2(12 - C) + 4C = 32

Simplify:
24 - 2C + 4C = 32

Combine like terms:
2C = 8

Divide both sides by 2:
C = 4

Now, substitute this value of C into equation 1 to find D:

D + 4 = 12
D = 12 - 4
D = 8

Therefore, there were 8 ducks and 4 cows on the farm.