Question

You have 149 coins in a jar they are a combination of dimes and quarters if the money in the jar equals to 22.70 how many of each coin type is there. Use elimination or substitution

Answer 1

Let x = number of dimes
Let y = number of quarters

x + y = 149

0.10x + 0.25y = 22.70

0.15x = 22.70 - 0.25y

x = (22.70 - 0.25y) / 0.15

x + y = 149

(22.70 - 0.25y) / 0.15 + y = 149

22.70 - 0.25y + 0.15y = 149 * 0.15

22.70 + 0.15y = 22.35

0.15y = 22.35 - 22.70

y = (22.35 - 22.70) / 0.15

y = -2.5

Since y cannot be negative, there are no solutions to this system of equations.

Answer 2

AAAaannndd the bot gets it wrong yet again!

d+q = 149
10d+25q = 2270
so there are 97 dimes and 52 quarters