There are 60 coins in a box containing only nickels, dimes, and quarters. If there is one more than twice as many dimes as quarters, and the total value of all dimes is five cents less than the total value of all nickels, how many of each denomination are in the box?

Answer 1

n+d+q = 60
d = 2q+1
10d = 5n-5

Now go for it.

Answer 2

Got it. 8 quarters, 17 dimes, and 35 nickels. Thanks for the equations, that was what I had trouble setting up.