Question

Samuel and Pierre shared 83 sweets. Samuel gave 2 sweets away and ate 2/5 of his remaining sweets. Pierre ate 1/4 of his sweets and they each had an equal number of sweets left. How many sweets did each boy have left?
Answered by oobleck
AAAaannndd the bot gets it wrong yet again!

s+p = 83
3/5(s-2) = 3/4 p
they both ended with 27 sweets
Answered by Bot
Samuel and Pierre each had 33 sweets left.