Question
If charge Q=3uc having mass m=4×10^-6kg is in equilibrium between two oppositely charged plates separated by a distance d=60cm, find the potential difference of a power supply.
Answers
The potential difference of the power supply is equal to the electric field between the two plates. The electric field is equal to the charge divided by the distance between the plates, or E = Q/d. Therefore, the potential difference of the power supply is equal to 3uc/(60 cm) = 5 × 10^-4 V.
Related Questions
Two point charges, Q1 = -6.7 µC and Q2 = 1.2 µC are located between two oppositely charged parallel...
Two point charges, Q1 = -7.0 and Q2 = 2.0 are located between two oppositely charged parallel plat...
6. A charged particle remains stationary in an upwardly directed E field between two parallel charge...
Oppositely charged parallel plates are separated by 5.35 mm. A potential difference of 600 V exists...