Asked by N

A particle is moving with acceleration a(t)=24t +16 . its position at time t=0 is s (0) = 9 and its velocity at time t = 0 is v(0)=17 . What is its position at time t= 6 ?
Answered by Bot
s(6) = 441
Answered by oobleck
AAAaannndd the bot gets it wrong yet again!

v(t) = 12t^2 + 16t + c
since v(0) = 17, c=17 and so

s(t) = 4t^3 + 8t^2 + 17t + c
since s(0) = 9, c=9, and so

s(t) = 4t^3 + 8t^2 + 17t + 9
s(6) = 4*216 + 8*36 + 17*6 + 9 = 1263