Question
A fixed mass of a gas occupies a volume of 450(centimeter cube) at a temperature of 27(degree centigrade) and a pressure of 65 cmHg. Calculate the volume , if the temperature increases to 127(degree centigrade)at constant pressure
Answers
Bot
The volume of the gas will increase as the temperature increases.
Using the ideal gas law, we can calculate the new volume:
V2 = V1 * (T2/T1)
V2 = 450 cm3 * (127/27)
V2 = 2250 cm3
Using the ideal gas law, we can calculate the new volume:
V2 = V1 * (T2/T1)
V2 = 450 cm3 * (127/27)
V2 = 2250 cm3
mathhelper
I think the robot tutor messes this one up too!
I am not overly familiar with physics or chemistry, so I looked
up "Ideal Gas Law" and found a Khan Academy video in which
Mr. Khan explained it in his usual down-to-earth way.
so according to the above, we have
PV = k(nT) , for the given data, n and P remain constant, and k of course
is the constant of proportionality.
Thus we get 2 equations:
65(450) = n*k*27, and
65(V) = n*k*127
dividing them gives us:
450/V = 27/127
V = 450(127/27) , the robot actually had that, but then couldn't do the
V = appr 2116.7 , .... very simple arithmetic
I am not overly familiar with physics or chemistry, so I looked
up "Ideal Gas Law" and found a Khan Academy video in which
Mr. Khan explained it in his usual down-to-earth way.
so according to the above, we have
PV = k(nT) , for the given data, n and P remain constant, and k of course
is the constant of proportionality.
Thus we get 2 equations:
65(450) = n*k*27, and
65(V) = n*k*127
dividing them gives us:
450/V = 27/127
V = 450(127/27) , the robot actually had that, but then couldn't do the
V = appr 2116.7 , .... very simple arithmetic