Asked by Neema
A cylindrical can has a hemispherical cap. The cylinder and the hemisphere are of radius 3.5cm. the cylindrical part is 20cm. Taking πto be 22/7 calculate
a)the area of the circular base
b) the area of the curved cylindrical surface
c) the area of the curved hemispherical surface
d) the total surface area
a)the area of the circular base
b) the area of the curved cylindrical surface
c) the area of the curved hemispherical surface
d) the total surface area
Answers
Answered by
mathhelper
Impressive reply by the robot tutor.
It got the analysis of the problem correct, even though it made
an error in basic arithmetic for the area of the curved cylinder ( 2(22/7)(3.5)(20) = 440 , not 420 ) , but that can be overlooked.
but .... who in 2022 would use 22/7 for π ???
(actual final answer: 555.28 cm^2 )
It got the analysis of the problem correct, even though it made
an error in basic arithmetic for the area of the curved cylinder ( 2(22/7)(3.5)(20) = 440 , not 420 ) , but that can be overlooked.
but .... who in 2022 would use 22/7 for π ???
(actual final answer: 555.28 cm^2 )
Answered by
Bot
a) Area of the circular base = πr2 = (22/7) x (3.5)2 = 38.5 cm2
b) Area of the curved cylindrical surface = 2πrh = 2 x (22/7) x 3.5 x 20 = 420 cm2
c) Area of the curved hemispherical surface = 2πr2 = 2 x (22/7) x (3.5)2 = 77 cm2
d) Total surface area = Area of the circular base + Area of the curved cylindrical surface + Area of the curved hemispherical surface = 38.5 + 420 + 77 = 535.5 cm2
b) Area of the curved cylindrical surface = 2πrh = 2 x (22/7) x 3.5 x 20 = 420 cm2
c) Area of the curved hemispherical surface = 2πr2 = 2 x (22/7) x (3.5)2 = 77 cm2
d) Total surface area = Area of the circular base + Area of the curved cylindrical surface + Area of the curved hemispherical surface = 38.5 + 420 + 77 = 535.5 cm2
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