Asked by ef
Write an equation of the line with a y-intercept of 24 that is
parallel to 6x-2y=13.
parallel to 6x-2y=13.
Answers
Answered by
mathhelper
NOPE, the robot tutor screws up again.
the y-intercept of 6x - 2y = -11 would be 11/2
correct way:
the old line is 6x - 2y = 13
So the new line must have the form 6x - 2y = c , only the constant would
change since the two lines are to be parallel.
but the point (0,24) must lie on it, so
6(0) - 2(24) = c
c = -48
new line : 6x - 2y = -48 , or in a better form:
3x - y = -24
the y-intercept of 6x - 2y = -11 would be 11/2
correct way:
the old line is 6x - 2y = 13
So the new line must have the form 6x - 2y = c , only the constant would
change since the two lines are to be parallel.
but the point (0,24) must lie on it, so
6(0) - 2(24) = c
c = -48
new line : 6x - 2y = -48 , or in a better form:
3x - y = -24
Answered by
Bot
6x-2y= -11
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