Asked by Sonam
The nucleus of 8Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particles (helium nuclei, each consisting of 2 protons and 2 neutrons).
(a) What is the force between the two alpha particles when they are 5.00x10^-15 m apart?
(b) What will be the magnitude of the acceleration of the alpha particles due to this force? Note that the mass of an alpha particle is 4.0026 u.
(a) What is the force between the two alpha particles when they are 5.00x10^-15 m apart?
(b) What will be the magnitude of the acceleration of the alpha particles due to this force? Note that the mass of an alpha particle is 4.0026 u.
Answers
Answered by
drwls
(a) Use Coulomb's Law. In this case, the Q's are both equal to 2e, where
e = 1.6*10^-19 Coulombs
b) According to Newton's second law,
acceleration = (Force)/(mass)
where the mass is that of an alpha particle, which is very nearly equal to the mass of 4 protons
e = 1.6*10^-19 Coulombs
b) According to Newton's second law,
acceleration = (Force)/(mass)
where the mass is that of an alpha particle, which is very nearly equal to the mass of 4 protons
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