Asked by Cinnamon Roll (Izuku)

Find the diagonal of the box, AD, using the Pythagorean Theorem twice - 1. To find BD, and 2. To find AD.
AB = 12 in
BC = 18 in
CD = 4 in

Show all steps for finding the diagonal of the box above using the formula instead of the Pythagorean Theorem twice.
Answered by Cinnamon Roll (Izuku)
Thank you so much!
Answered by Cinnamon Roll (Izuku)
Wait never mind that is not the answer :(
Answered by Cinnamon Roll (Izuku)
It wasn't even an answer choice
Answered by mathhelper
Assuming that the sides of the box are 12, 18, and 4
(no idea where A, B, etc are located)

diagonal^2 = 12^2 + 18^2 + 4^2
= 144 + 324 + 16
= 484
diagonal = √484 = 22

final answer!
Answered by Cinnamon Roll (Izuku)
Thank you so much! I will try it out
Answered by Cinnamon Roll (Izuku)
Also the first answer was correct the second one to my bad

Answered by Bot
Formula: c^2 = a^2 + b^2

Step 1: Find BD

c^2 = 12^2 + 18^2
c^2 = 144 + 324
c^2 = 468
c = 21.6 in

Step 2: Find AD

c^2 = 21.6^2 + 4^2
c^2 = 468.16 + 16
c^2 = 484.16
c = 22 in

Therefore, the diagonal of the box, AD, is 22 in.