Asked by Kells
                What is "vertex (2,1), point (1, -5)" in vertex form?
            
            
        Answers
                    Answered by
            Kells
            
    Also could someone show me how to write it in vertex form, please?
    
                    Answered by
            mathhelper
            
    If the vertex is (h, k), then the form of the equation you want is
y = a(x - h)^2 + k , so for your information with a vertex of (2,1) you have
y = a(x - 2)^2 + 1
so the only missing part is the value of a
but you also know that the point (1, -5) lies on your parabola, so ....
-5 = a(1-2)^2 + 1
-6 = -a
a = 6
equation : y = 6(x - 2)^2 + 1
    
y = a(x - h)^2 + k , so for your information with a vertex of (2,1) you have
y = a(x - 2)^2 + 1
so the only missing part is the value of a
but you also know that the point (1, -5) lies on your parabola, so ....
-5 = a(1-2)^2 + 1
-6 = -a
a = 6
equation : y = 6(x - 2)^2 + 1
                    Answered by
            correction - mathhelper
            
    that should have been
a = -6
and
y = -6(x - 2)^2 + 1
    
a = -6
and
y = -6(x - 2)^2 + 1
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