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Log5(5squareroot x/7) the first 5 is a base

how would you expand that?

1 answer

log(base5) of 5 sqrtx/7)
= log (base5) 5 + log(base5)x^1/2 - log(base5) 7
= 1 + (1/2) log(base5) x - 1.20906
= (1/2) log(base5)x - 0.20906

I assumed that your square root was of x, not of x/7
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