Asked by nito
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
Answers
Answered by
oobleck
the slope is -7/2
so the point-slope form is
y = -7/2 (x+3) + 11
2y = -7x - 21 + 22
so the standard form is
7x+2y = 1
so the point-slope form is
y = -7/2 (x+3) + 11
2y = -7x - 21 + 22
so the standard form is
7x+2y = 1
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