Asked by Tamera

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
Answered by Reiny
slope JK = (3+5)/(-6+4) = 8/-2 = -4

so you have
y = -4x + b

plug in either point and solve for b

What did you get ?
Answered by Anonymous
Line j passes through points (8, 10) and (4, 1). Line k is parallel to line j. What is the slope of line k?
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