Asked by Anonymous
Six consecutive numbers add up to a total of 45. What is the highest of these numbers?
Answers
Answered by
mathhelper
let the numbers be
x, x+1, x+2, x+3, x+4, x+5
adding them:
6x + 15 = 45
6x = 30
x = 5
the largest is x+5 = .......
x, x+1, x+2, x+3, x+4, x+5
adding them:
6x + 15 = 45
6x = 30
x = 5
the largest is x+5 = .......
Answered by
oobleck
or, consider if they were all the same: 45/6 = 15/2 = 7.5
Now you know that there are 3 above and three below this, so they are
5,6,7,8,9,10
Now you know that there are 3 above and three below this, so they are
5,6,7,8,9,10
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