Asked by Sofia
Log10 base 5(3/5)+3 log(15/2) base 5- log(81/8) base 5
Answers
Answered by
oobleck
so, with all logs base 5, we have (not sure what to do with the (3/5)
log10 + 3log(15/2) - log(81/8)
= log2 + log5 + 3log5 + 3log3 - 3log2 - 4log3 + 3log2
= 4log2 - 2log3 + 4log5
= log <sub>5</sub>144 + 4
maybe if you fix your typo you can sraighten it out
log10 + 3log(15/2) - log(81/8)
= log2 + log5 + 3log5 + 3log3 - 3log2 - 4log3 + 3log2
= 4log2 - 2log3 + 4log5
= log <sub>5</sub>144 + 4
maybe if you fix your typo you can sraighten it out
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