Asked by Taylor
Solve the equation over the interval [0,2π)
4csc^2+1 = 0
4csc^2+1 = 0
Answers
Answered by
Reiny
4csc^2 = -1
csc^2 = -1/4
no need to go any further.
The square of "something" cannot be negative.
no solution
csc^2 = -1/4
no need to go any further.
The square of "something" cannot be negative.
no solution
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