Asked by Anonymous
                If 𝑎 = sin70°,𝑏 = cos70°,𝑐 = tan70°,𝑑 = 1 , order them from the largest to the smallest.
            
            
        Answers
                    Answered by
            mathhelper
            
    Superimpose the sine, the cosine, and the tangent function and look at 70°
to see that it would be
b < a < 1 < d
Or you could use your calculator and find their values,
Or ,
cosx starts at 1 and decreases with cos90° = 0
since 70 is close to 90 cos70 must be closer to 0 than 1
sinx starts at 0 and increases with sin90 = 1
since 70° is close to 90, sin70 must be closer to 1 than 0, so sin70 > cos70
neither sinx nor cosx are at 1 for x = 70, so 1 must be 3rd
tanx goes from 0 to infinitiy with tan 45° = 1
since 70 > 45, tan 70 > 1
so we have b < a < d < c
    
to see that it would be
b < a < 1 < d
Or you could use your calculator and find their values,
Or ,
cosx starts at 1 and decreases with cos90° = 0
since 70 is close to 90 cos70 must be closer to 0 than 1
sinx starts at 0 and increases with sin90 = 1
since 70° is close to 90, sin70 must be closer to 1 than 0, so sin70 > cos70
neither sinx nor cosx are at 1 for x = 70, so 1 must be 3rd
tanx goes from 0 to infinitiy with tan 45° = 1
since 70 > 45, tan 70 > 1
so we have b < a < d < c
                    Answered by
            oobleck
            
    sinx = cosx at x = 45°
since sinx is increasing and cosx is decreasing, cosx < sinx at x=70°
and, since tanx > 1 for x > 45°,
cosx < sinx < tanx
    
since sinx is increasing and cosx is decreasing, cosx < sinx at x=70°
and, since tanx > 1 for x > 45°,
cosx < sinx < tanx
                    Answered by
            oobleck
            
    oh, and since secx > tanx, add that to the list as greatest
    
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