Asked by kate
At what distance would the repulsive force between two electrons have a magnitude of 8.50 N? I have no idea how to do this problem... can someone help me please... 3x10^-4/8.50?
Answers
Answered by
drwls
Use Coulomb's law.
F = k Q^2/R^2
In this case, Q is the electron charge and R is the separation distance.
Set F = 8.50 N and solve for the separation R. Your course material should tell you the value of k, if you do not know it. You can also find it many places online, such as http://www.glenbrook.k12.il.us/gbssci/phys/Class/estatics/u8l3b.html
F = k Q^2/R^2
In this case, Q is the electron charge and R is the separation distance.
Set F = 8.50 N and solve for the separation R. Your course material should tell you the value of k, if you do not know it. You can also find it many places online, such as http://www.glenbrook.k12.il.us/gbssci/phys/Class/estatics/u8l3b.html
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