Question
A 0.268g sample of a polypeptide was dissolved in water and made up to a volume of 160mL at 31.0°C. At this temperature the osmotic pressure of this solution was 4.41mmHg. Calculate the molecular mass of the polypeptide
Answers
DrBob222
pi = MRT
4.41mm/760mm = M*0.08205*(273+31)
0.00580/0.08205*304 = M = moles/L 0 000233
0.000233 = mols/0.160 L. Solve for moles, then moles = grams/molar mass. You have moles and grams. solve for molar mass.
Confirm those calculations.
4.41mm/760mm = M*0.08205*(273+31)
0.00580/0.08205*304 = M = moles/L 0 000233
0.000233 = mols/0.160 L. Solve for moles, then moles = grams/molar mass. You have moles and grams. solve for molar mass.
Confirm those calculations.