Asked by Anonymous
A steel ball rolls with constant velocity across a tabletop 0.950m high. IT rolls off and hits the ground +0.352m horizontally from the edge of the table.what are the horizontal and vertical component velocity of the ball just before it hits the ground?
Answers
Answered by
oobleck
how long doers it take to hit?
4.9t^2 = 0.95
now, the velocity components are
Vy = -9.8t
Vx = 0.352/t
4.9t^2 = 0.95
now, the velocity components are
Vy = -9.8t
Vx = 0.352/t
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