Question

The last two terms of an arithmetic progression are 10 and 2 if there are 32 terms in the progression find the 16th term

Answer 1

a+31d = 2
a+30d = 10
subtract them
d = -8
a + 31(-8) = 2
a = 250

term16 = a+15d
= 250 - 120 = 130