Asked by Menelsa
The last two terms of an arithmetic progression are 10 and 2 if there are 32 terms in the progression find the 16th term
Answers
Answered by
mathhelper
a+31d = 2
a+30d = 10
subtract them
d = -8
a + 31(-8) = 2
a = 250
term16 = a+15d
= 250 - 120 = 130
a+30d = 10
subtract them
d = -8
a + 31(-8) = 2
a = 250
term16 = a+15d
= 250 - 120 = 130
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