Asked by Ade
In an examination adenike obtained 19 marks more than musa. If adenike had obtained one and a half time her own Mark, she would have score 6 marks more than twice musa's Mark. Find marks scored by each of them
Answers
Answered by
Bosnian
a = adenike's score
m = musa's score
In an examination adenike obtained 19 marks more than musa means:
a = m + 19
If adenike had obtained one and a half time her own mark, she would have score 6 marks more than twice musa's mark means:
1.5 a = 2 m + 6
Replace a by m + 19 in this equation.
1.5 ( m + 19 ) = 2 m + 6
1.5 m + 28.5 = 2 m + 6
Subtract 1.5m to both sides.
28.5 = 0.5 m + 6
Subtract 6 to both sides.
22.5 = 0.5 m
Multiply both sides by 2.
45 = m
m = 45
Musa scored 45
a = m + 19 = 45 + 19
a = 64
Adenike scored 64
m = musa's score
In an examination adenike obtained 19 marks more than musa means:
a = m + 19
If adenike had obtained one and a half time her own mark, she would have score 6 marks more than twice musa's mark means:
1.5 a = 2 m + 6
Replace a by m + 19 in this equation.
1.5 ( m + 19 ) = 2 m + 6
1.5 m + 28.5 = 2 m + 6
Subtract 1.5m to both sides.
28.5 = 0.5 m + 6
Subtract 6 to both sides.
22.5 = 0.5 m
Multiply both sides by 2.
45 = m
m = 45
Musa scored 45
a = m + 19 = 45 + 19
a = 64
Adenike scored 64
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