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C8H16 + 12O2 ==> 8CO2 + 8H2O
13.5 L C8H18 x 1 mol/22.4 L = ? mol
How many moles of C8H16 are used when 13.25 liters of C8H16 gas are used, measured at STP, in an excess of oxygen?
Give two decimal places in your answer and no units.
13.5 L C8H18 x 1 mol/22.4 L = ? mol