Asked by ann
Two forces p and q have magnitude of 22N and 17N respectively. The resultant of the forces is R . If the angle between Q and R is 30
@. find the angle between P and R
@the magnitude of R
@. find the angle between P and R
@the magnitude of R
Answers
Answered by
ann
17\sinθ=22/sin30
22 sinθ= 17sin30÷22
sinθ=17×0.5÷22=8.5÷22
sinθ=0.3864
θ=sin-¹ 0.3864
θ=22.73°
:the angle between p and q
=22.73°
θ+30°+@(alpha),=180°
22.73°+30°+@=180°
52.73°+@=180°
@=180°-52.73°
@=127.27°
R²=17²+22²-2×17×22cos127.27
R²=289+484-748×-0.605
R²=773+452.98
R²=1225.98
R=√1225.98
R=35.01N
: the resultant force is
=35.01N
22 sinθ= 17sin30÷22
sinθ=17×0.5÷22=8.5÷22
sinθ=0.3864
θ=sin-¹ 0.3864
θ=22.73°
:the angle between p and q
=22.73°
θ+30°+@(alpha),=180°
22.73°+30°+@=180°
52.73°+@=180°
@=180°-52.73°
@=127.27°
R²=17²+22²-2×17×22cos127.27
R²=289+484-748×-0.605
R²=773+452.98
R²=1225.98
R=√1225.98
R=35.01N
: the resultant force is
=35.01N
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