Asked by Amy
I just need someone to show me how these problems are done then i can do them myself
The Ka values of H2CO3 are shown below.
Ka1 4.6 10-7
Ka2 4.4 10-11
What is the pH of a 0.15 M solution of Na2CO3?
that one i tried to write out all the equations witht heir Ka then what?
how do u use .15 of the Na2CO3 thing?
The Ka values of H2CO3 are shown below.
Ka1 4.6 10-7
Ka2 4.4 10-11
What is the pH of a 0.15 M solution of Na2CO3?
that one i tried to write out all the equations witht heir Ka then what?
how do u use .15 of the Na2CO3 thing?
Answers
Answered by
DrBob222
The pH of a sodium carbonate solution is determined by the hydrolysis of the salt, in this case the carbonate ion.
CO3^-2 + HOH ==> HCO3^- OH^-
Write the Keq expression, set up an ICE chart, (Keq is Kb for carbonate ion which will be K2 for the acid). Solve for OH^-, convert to pOH, then to pH.
CO3^-2 + HOH ==> HCO3^- OH^-
Write the Keq expression, set up an ICE chart, (Keq is Kb for carbonate ion which will be K2 for the acid). Solve for OH^-, convert to pOH, then to pH.
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