Asked by Mahdiyya

Hookes law states that the first F in a spring extended by a length X is given by f = - kx according to Newton second law of motion f= ma calculate the dimensions of the spring constant k

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Answered by Mahdiyya
Hookes law states that the first F in a spring extended by a length X is given by f= - kx according to Newton second law of motion f= ma calculate the dimensions of the spring constant k
Answered by oobleck
since F is the same,
kx = ma
so in units,
k*m = kg * m/s^2
k = kg/s^2
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