Asked by Niz sew
                Hookes law states that the force , F in a spring extended by length x is given by F=-Kx. According to Newton's second law F=ma, where m is the mass and a is the acceleration.  Calculate the dimension of the spring constant k.
            
            
        Answers
                    Answered by
            R_scott
            
    -K x = m a
-K ⋅ meters = kg ⋅ m/s^2 = Newtons
K = - N / m
the spring force increases linearly (directly proportional to the stretch)
... in the direction opposite the elongation (stretching)
    
-K ⋅ meters = kg ⋅ m/s^2 = Newtons
K = - N / m
the spring force increases linearly (directly proportional to the stretch)
... in the direction opposite the elongation (stretching)
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.