Asked by Niz sew
Hookes law states that the force , F in a spring extended by length x is given by F=-Kx. According to Newton's second law F=ma, where m is the mass and a is the acceleration. Calculate the dimension of the spring constant k.
Answers
Answered by
R_scott
-K x = m a
-K ⋅ meters = kg ⋅ m/s^2 = Newtons
K = - N / m
the spring force increases linearly (directly proportional to the stretch)
... in the direction opposite the elongation (stretching)
-K ⋅ meters = kg ⋅ m/s^2 = Newtons
K = - N / m
the spring force increases linearly (directly proportional to the stretch)
... in the direction opposite the elongation (stretching)
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