Asked by Grace

The 14th term of an arithmetic progression is 96 while the 25th term is 173 find the sum of the 13th term and the 56th
Answered by oobleck
a+13d = 96
a+24d = 173
solve for a and d, and then you want
a+12d + a+55d = 2a+67d
Answered by Grace
T14=96. T25 =173. Nth term TN=at(n-1) d t14=at(14-1)d. T14 =a+(13)d t14=a+13d but t14=96 =a+13d a+13d=96 T25=a+(25-1)d T25 =a+24d T25 =173 173 =a+24d.


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