Asked by Anonymous
Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the y=mx+b. (2,6); 5x+y=8
Answers
Answered by
mathhelper
simplest way:
since the new line must be perpendicular to the given line 5x + y = 8
the new line must be x - 5y = c, but (2,6) must be on it, so
2 - 5(6) = x = -28
new line : x - 5y = -28
in the form you want:
-5y = -x - 28
y = (1/5)x + 28/5
since the new line must be perpendicular to the given line 5x + y = 8
the new line must be x - 5y = c, but (2,6) must be on it, so
2 - 5(6) = x = -28
new line : x - 5y = -28
in the form you want:
-5y = -x - 28
y = (1/5)x + 28/5
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