Asked by Odege
What work is done by a force 20n on a spring when the application of this force causes an extension 10cm in the spring?
Answers
Answered by
oobleck
F = kx
W = 1/2 kx^2 = 1/2 (F/x) x^2 = 1/2 Fx = 1/2 * 20 * 0.1 = 1 J
W = 1/2 kx^2 = 1/2 (F/x) x^2 = 1/2 Fx = 1/2 * 20 * 0.1 = 1 J
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