Asked by Anonymous
                Out of five men and five women, we form a committee consisting of four different people. Assuming that each committee of size four is equally likely, find the probabilities of the following events:
            
            
        Answers
                    Answered by
            mathhelper
            
    Looks like you are just choosing any 4 of the 9 people, since no conditions
were stated, so that is simply
C(9,4) or 126
9!/(4!5!) = 362880/(24*120) = 126
    
were stated, so that is simply
C(9,4) or 126
9!/(4!5!) = 362880/(24*120) = 126
                    Answered by
            mathhelper
            
    looks like your question is incomplete
    
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