Ask a New Question

Asked by Gabriela

How can I find the horizontal asymptote of:

y=e^x/(2e^x+5)

i know you have to do the limit as x approaches infinity... but that is about all i know...

mulitply the numberator and denominator by e^-x

y= e^0/(2e^0 + 5e^-x)

y= 1/(2 + 5e^-x)

now, take lim as x >> int. Notice the e^-x goes to zero.

y= 1/2 as x approaches zero.
18 years ago

Answers

Related Questions

How do you find the horizontal tangent for the equation f(x)=x^2-3? Algebraically find all the horizontal and vertical asymptoes of the functions f(x)=x/(x-1) q(x)=(x-1)/x how do you find the horizontal and vertical assymptotes of the curve y= x/ x+3 and also the inter... How do you find the Horizontal Asymptote of y= (x+2)/(x-6)? how do u find the horizontal force needed to push a wheel that weighs 300N and has a radius of 30m.i... Find the horizontal and vertical components of the velocity of a cannonball 4 seconds after being f... Find the horizontal and vertical asymptotes of the curve. y = 3x+6/x−7 x= y= Find the horizontal and vertical asymptotes of the curve. y = 7e^x/e^x−8 x=? y=?(smaller y-val... how do i find the horizontal velocity (m/s) when i have the angle, the time, and horizontal range? How do i find the horizontal asymptote of [1/(x-5)]+4
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use