Asked by Christina
Solve 2x²-12+36=0 by completing the square
Answers
Answered by
oobleck
2x^2 - 12x + 36 = 0
x^2 - 6x + 18 = 0
x^2 - 6x + 9 = -9
(x-3)^2 = -9
x = 3±3i
x^2 - 6x + 18 = 0
x^2 - 6x + 9 = -9
(x-3)^2 = -9
x = 3±3i
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