Asked by hit786
Jim’s dog Sparky runs 50 m northeast to a tree, then 70 m west to a second tree,
and finally 20 m south to a third tree.
a. Draw a picture and establish a coordinate system.
b. Calculate Sparky’s net displacement in component form.
c. Calculate Sparky’s net displacement as a magnitude and an angle.
and finally 20 m south to a third tree.
a. Draw a picture and establish a coordinate system.
b. Calculate Sparky’s net displacement in component form.
c. Calculate Sparky’s net displacement as a magnitude and an angle.
Answers
Answered by
Anonymous
East = x = 50 cos 45 -70 = -34.6
North = y = 50 sin 45 - 20 = 15.4
magnitude = sqrt (34.6^2 + 15.4^2 )
angle north of east = tan^-1 (-15.4/34.6)
North = y = 50 sin 45 - 20 = 15.4
magnitude = sqrt (34.6^2 + 15.4^2 )
angle north of east = tan^-1 (-15.4/34.6)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.