Question

Given that x2+y2=5xy, show that log(x-y/√3)=1/2(logx+logy)
x^2 + y^2 = 5xy
x^2 - 2xy + y^2 = 5xy - 2xy
(x-y)^2 = 3xy

(x-y)^2/3 = xy
Now finish it off. Post your work if you get stuck

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Hi, I need help with a problem about power functions and logarithms. It is found that logx and... Logx + logy=4 logx +2logy=3 show that the sum of nterm of the progression is logx,logx^2,logx^3,logx^4---is n(n+1)/2 logx Given that x²+y=5xy show that A) 2log(x+y/√7)=logx+logy B)log(x-y/√3)=½(logx+logy)