Asked by Dawn
Given that x²+y=5xy show that
A) 2log(x+y/√7)=logx+logy
B)log(x-y/√3)=½(logx+logy)
A) 2log(x+y/√7)=logx+logy
B)log(x-y/√3)=½(logx+logy)
Answers
Answered by
oobleck
Fixing your typo, we have
x^2 + y^2 = 5xy
equating A and B,
log (x+y)^2/7 = log(x-y)^2/3
3(x+y)^2 = 7(x-y)^2
3x^2 + 6xy + 3y^2 = 7x^2 - 14xy + 7y^2
4x^2 - 20xy + 4y^2 = 0
x^2 + y^2 = 5xy
So see what you can do with A and B separately.
x^2 + y^2 = 5xy
equating A and B,
log (x+y)^2/7 = log(x-y)^2/3
3(x+y)^2 = 7(x-y)^2
3x^2 + 6xy + 3y^2 = 7x^2 - 14xy + 7y^2
4x^2 - 20xy + 4y^2 = 0
x^2 + y^2 = 5xy
So see what you can do with A and B separately.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.