Question

How would I go about solving this equation algebraically?

Find the equation of the parabola

y=ax^2 + bx+c

that passes through the given points.

(2,0) (3,-1) (4,0)

Thanks.

Answer 1

Sketch a graph.
see that vertex is at (3.-1)
so form is
(y+1) = k(x-3)^2
substitute in (2,0) to find k
1 = k (-1)^2
k = 1
so
y = (x-3)^2
or
y = x^2 - 6 x + 9

Answer 2

I plugged that into my graphing calculator and that isn't right. Could someone help?